On 11.11.2009, at 02:03, Benjamin Herrenschmidt wrote:
+ li r4,0
mfspr r5,SPRN_HID5
r5 = *HID5
So far so good...
- rldimi r5,r5,6,56
Take r5, remove some bits, write into r5
Hrm... nope :-)
rldimi will insert into the destination (r5) bits 56..57
the corresponding bits from the source (r5) after that source has been
rotated left by 6 bits.
That means inserting the 2 low bits of r5 into r5[56:57] afaik :-)
+ rldimi r5,r4,6,56
Take r4, remove some bits, write into r5.
My variant will insert the bits from r4 which is 0, means it's going
to
insert 0's in r5[56:57] which is what you want (clear the two dcbz
special bits) right ?
Or did I miss anything?
I think you did :-)
Wow, and there I thought I finally mastered the rotate instructions :-).
Alex
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