Fwd: Re: [PATCH] uts: Don't randomize "struct uts_namespace".

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Subject: Re: [PATCH] uts: Don't randomize "struct uts_namespace".
To: Linus Torvalds <torvalds@xxxxxxxxxxxxxxxxxxxx>, Ken'ichi Ohmichi <oomichi@xxxxxxxxxxxxxxxxx>, Masaki Tachibana <mas-tachibana@xxxxxxxxxxxxx>, Kazuhito Hagio <k-hagio@xxxxxxxxxxxxx>
Cc: Kees Cook <keescook@xxxxxxxxxxxx>, Linux Kernel Mailing List <linux-kernel@xxxxxxxxxxxxxxx>
From: Tetsuo Handa <penguin-kernel@xxxxxxxxxxxxxxxxxxx>
Date: Sat, 7 Jul 2018 08:10:08 +0900

Hello Ken'ichi,

I noticed that makedumpfile ( https://sourceforge.net/p/makedumpfile/code/ )
can no longer detect kernel version correctly because "struct uts_namespace"
(which is exposed to userspace via vmcoreinfo) is subjected to randomization
by GCC_PLUGIN_RANDSTRUCT kernel config option since 4.13.

The code was introduced by below commit.

  commit bfc8fe181c822ad0d8495ceda3c7109a407192f0
  Author: ken1_ohmichi <ken1_ohmichi>
  Date:   Fri Dec 22 07:41:14 2006 +0000

      linux-2.6.19 support.
      On linux-2.6.18 or former, the release information could be gotten from
      the symbol "system_utsname". But on linux-2.6.19, it can be done from the
      symbol "init_uts_ns". A new makedumpfile can get the release information
      from the existing symbol.

Can you detect kernel version without using "struct uts_namespace" ?

On 2018/07/07 1:11, Linus Torvalds wrote:
> On Fri, Jul 6, 2018 at 3:07 AM Tetsuo Handa
> <penguin-kernel@xxxxxxxxxxxxxxxxxxx> wrote:
>>
>> I noticed that makedumpfile utility is failing to check kernel version, for
>> it depends on offset of "struct uts_namespace"->name being sizeof(int).
> 
> For something like this, we fix makedumpfile instead. This is not a
> "user program" using system calls etc, this is something that delves
> into the kernel dump and tries to make sense of it.
> 
> Where is the makedumpfile source code? What is it trying to do, and why?
> 
> One option is to just say "hey, you can't make much sense of a
> randomized kernel dump anyway, so don't even try".
> 
>                  Linus
> 


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