Description
in dump_dmesg_structured() the out_buf size is 4096, and if the
length is less than 4080( 4096-16 ) it won't really write out.
Normally, after writing one or four chars to the out_buf, it will
check the length of out_buf. But in extreme cases, 19 chars was
written to the out_buf before checking the length. This may cause
the stack corruption. If the length was 4079 (won't realy write out),
and then write 19 chars to it. the out_buf will overflow.
Solution
Change 16 to 64 thus can make sure that always have 64bytes before
moving to next records. why using 64 is that a long long int can take
20 bytes. so the length of timestamp can be 44 ('[','.',']',' ') in
extreme case.
Signed-off-by: arthur <zzou at redhat.com>
---
vmcore-dmesg/vmcore-dmesg.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/vmcore-dmesg/vmcore-dmesg.c b/vmcore-dmesg/vmcore-dmesg.c
index 0345660..e15cd91 100644
--- a/vmcore-dmesg/vmcore-dmesg.c
+++ b/vmcore-dmesg/vmcore-dmesg.c
@@ -674,7 +674,7 @@ static void dump_dmesg_structured(int fd)
else
out_buf[len++] = c;
- if (len >= OUT_BUF_SIZE - 16) {
+ if (len >= OUT_BUF_SIZE - 64) {
write_to_stdout(out_buf, len);
len = 0;
}
--
1.8.4.2
