On Wed, Nov 21, 2012 at 11:52 AM, H. Peter Anvin <hpa at zytor.com> wrote:
> On 11/21/2012 11:50 AM, Yinghai Lu wrote:
>>>
>>> So how do I force a 16bit or 32bit entry using a bzImage64?
>>
>> kexec -t bzImage -l ....
>> will load low and use 32bit entry.
>>
>> kexec -t bzImage64 -l ...
>> kexec -l ...
>> will try to load high and use 64bit entry.
>>
>
> I don't see any difference...
>
--- a/kexec/arch/x86_64/kexec-x86_64.c
+++ b/kexec/arch/x86_64/kexec-x86_64.c
@@ -37,6 +37,7 @@ struct file_type file_type[] = {
{ "multiboot-x86", multiboot_x86_probe, multiboot_x86_load,
multiboot_x86_usage },
{ "elf-x86", elf_x86_probe, elf_x86_load, elf_x86_usage },
+ { "bzImage64", bzImage64_probe, bzImage64_load, bzImage64_usage },
{ "bzImage", bzImage_probe, bzImage_load, bzImage_usage },
{ "beoboot-x86", beoboot_probe, beoboot_load, beoboot_usage },
{ "nbi-x86", nbi_probe, nbi_load, nbi_usage },
bzImage64_probe will be run before bzImage_probe.
and if it find that is 64bit, bzImage_probe will not be executed.
