Huang, Ying wrote: > The hibernation procedure with the patch set is as follow: > > 1. Boot a kernel A > > 2. Work under kernel A > > 3. Kexec another kernel B (crash dump enabled) in kernel A. > > 4. Save the memory image of kernel A through crash dump (such as "cp > /proc/vmcore ~"). Save the "jump back entry". Doesn't this also save the memory of kernel B? > 5. Shutdown or reboot > > > The restore process with the patch set is as follow: > > 1. Boot a kernel C (crash dump enabled), the memory area used by > kernel C must be a subset of memory area used by kernel B. Why is a third kernel needed? Why can't kernel B be used for this as well? In fact, if kernel A has been compiled to be relocatable and crash dump enabled, why wouldn't it suffice for all 3 instances?
