On Wed, Apr 25, 2007 at 08:03:04PM +0900, Fernando Luis V?zquez Cao wrote: > > static __inline__ void apic_wait_icr_idle(void) > { > while (apic_read(APIC_ICR) & APIC_ICR_BUSY) > cpu_relax(); > } > > The busy loop in this function would not be problematic if the > corresponding status bit in the ICR were always updated, but that does > not seem to be the case under certain crash scenarios. As an example, > when the other CPUs are locked-up inside the NMI handler the CPU that > sends the IPI will end up looping forever in the ICR check, effectively > hard-locking the whole system. > > Quoting from Intel's "MultiProcessor Specification" (Version 1.4), B-3: > > "A local APIC unit indicates successful dispatch of an IPI by > resetting the Delivery Status bit in the Interrupt Command > Register (ICR). The operating system polls the delivery status > bit after sending an INIT or STARTUP IPI until the command has > been dispatched. > > A period of 20 microseconds should be sufficient for IPI dispatch > to complete under normal operating conditions. If the IPI is not > successfully dispatched, the operating system can abort the > command. Alternatively, the operating system can retry the IPI by > writing the lower 32-bit double word of the ICR. This ?time-out? > mechanism can be implemented through an external interrupt, if > interrupts are enabled on the processor, or through execution of > an instruction or time-stamp counter spin loop." > > Intel's documentation suggests the implementation of a time-out > mechanism, which, by the way, is already being open-coded in some parts > of the kernel that tinker with ICR. > > --- Possible solutions > > * Solution A: Implement the time-out mechanism in apic_wait_icr_idle. > > The problem with this approach is that introduces a performance penalty > that may not be acceptable for some callers of apic_wait_icr_idle. > Besides, during normal operation delivery errors should not occur. This > brings us to solution B. > Hi Fernando, How much is the performance penalty? Is it really significant. My point is that, to me changing apic_wait_icr_dle() itself seems to be the simple approach instead of introducing another function. Original implementation is: static __inline__ void apic_wait_icr_idle(void) { while (apic_read(APIC_ICR) & APIC_ICR_BUSY) cpu_relax(); } And new one will look something like. do { send_status = apic_read(APIC_ICR) & APIC_ICR_BUSY; if (!send_status) break; udelay(100); } while (timeout++ < 1000); There will be at max 100 microsecond delay before you realize that IPI has been dispatched. To optimize it further we can change it to 10 microsecond delay do { send_status = apic_read(APIC_ICR) & APIC_ICR_BUSY; if (!send_status) break; udelay(10); } while (timeout++ < 10000); or may be do { send_status = apic_read(APIC_ICR) & APIC_ICR_BUSY; if (!send_status) break; udelay(1); } while (timeout++ < 100000); I don't know if 1 micro second delay is supported. I do see it being used in kernel/hpet.c Is it too much of performance overhead? Somebody who knows more about it needs to tell. To me changing apic_wait_icr_idle() seems simple instead of introducing a new function and then making a special case for NMI. Thanks Vivek