"if (nxt)" is always true, as it was checked in the while's condition.
io_wq_current_is_worker() is unnecessary, as non-async callers don't
pass nxt, so io_queue_async_work() will be called for them anyway.
Signed-off-by: Pavel Begunkov <asml.silence@xxxxxxxxx>
---
fs/io_uring.c | 11 +----------
1 file changed, 1 insertion(+), 10 deletions(-)
diff --git a/fs/io_uring.c b/fs/io_uring.c
index 63ef603d5fa0..1ab045e5d663 100644
--- a/fs/io_uring.c
+++ b/fs/io_uring.c
@@ -898,16 +898,7 @@ static void io_req_link_next(struct io_kiocb *req, struct io_kiocb **nxtptr)
nxt->flags |= REQ_F_LINK;
}
- /*
- * If we're in async work, we can continue processing the chain
- * in this context instead of having to queue up new async work.
- */
- if (nxt) {
- if (io_wq_current_is_worker())
- *nxtptr = nxt;
- else
- io_queue_async_work(nxt);
- }
+ *nxtptr = nxt;
break;
}
--
2.24.0
