Look at the first 16 characters of the user buffer and if they are all
printable, assume that user buffer contains ASCII data (e.g. a debug log)
that we want to simply print out. Otherwise, we treat it as a binary data
and hexdump as before.
Signed-off-by: Chris Wilson <chris@xxxxxxxxxxxxxxxxxx>
---
tools/intel_error_decode.c | 20 ++++++++++++++++++++
1 file changed, 20 insertions(+)
diff --git a/tools/intel_error_decode.c b/tools/intel_error_decode.c
index cdef3b18..84ef72b6 100644
--- a/tools/intel_error_decode.c
+++ b/tools/intel_error_decode.c
@@ -51,6 +51,7 @@
#include <assert.h>
#include <intel_bufmgr.h>
#include <zlib.h>
+#include <ctype.h>
#include "intel_chipset.h"
#include "intel_io.h"
@@ -434,6 +435,16 @@ print_fault_data(unsigned devid, uint32_t data1, uint32_t data0)
#define MAX_RINGS 10 /* I really hope this never... */
+static bool maybe_ascii(const void *data, int check)
+{
+ const char *c = data;
+ while (check--) {
+ if (!isprint(*c++))
+ return false;
+ }
+ return true;
+}
+
static void decode(struct drm_intel_decode *ctx,
const char *buffer_name,
const char *ring_name,
@@ -458,6 +469,15 @@ static void decode(struct drm_intel_decode *ctx,
drm_intel_decode_set_batch_pointer(ctx, data, gtt_offset,
*count);
drm_intel_decode(ctx);
+ } else if (maybe_ascii(data, 16)) {
+ char *c = (char *)data;
+ int max = 4 * *count;
+ for (int i = 0; i < max; i++) {
+ if (!c[i])
+ break;
+ putchar(c[i]);
+ }
+ putchar('\n');
} else {
for (int i = 0; i + 4 <= *count; i += 4)
printf("[%04x] %08x %08x %08x %08x\n",
--
2.15.0
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