Valdis.Kletnieks@xxxxxx writes: > Exactly. And the *reason* why IPv6 has 128 bit addresses is because > the designers realized that such losses happen, and ruled out 64-bit > addresses because of that effect. Since those losses are not significantly diminished by doubling the address length, why bother? The problem arises when zones of the address are reserved. Setting aside n bits of an m-bit address diminishes the address space by 2^n, not by (m-n)/m. > I suggest you figure out just how much bigger 2^65 is than the > current 2^32 ... 33 bits You're making the same mistake as everyone else: You calculate the size of the address space as 2^n, but you believe that reserving m bits diminishes the address space by only m.