Hello,
I'm trying to use the show-menu signal on GtkMenuToolButton with GTK+3.18. It works but I also have the signal on hide. Do I miss something ? It is the right behavior ?Thanks for the help.
Vincent
#include <gtk/gtk.h>
#include <stdio.h>
void show (GtkButton *button, void*)
{
printf ("eituan\n");
}
int main (int argc, char *argv[])
{
gtk_init (&argc, &argv);
GtkBuilder * build = gtk_builder_new ();
gtk_builder_add_from_file (build, "/home/legarrec/info/programmation/tmp/gtktest/main.ui", NULL);
GObject * obj = gtk_builder_get_object (build, "buttonUndo");
if (obj == NULL)
{
printf ("obj\n");
return 1;
}
g_signal_connect (obj, "show-menu", G_CALLBACK (show), NULL);
GtkWidget * p_win = (GtkWidget *) gtk_builder_get_object ( build, "window1");
gtk_widget_show_all (p_win);
gtk_main ();
}
<?xml version="1.0" encoding="UTF-8"?>
<interface>
<requires lib="gtk+" version="3.18"/>
<object class="GtkApplicationWindow" id="window1">
<property name="can_focus">False</property>
<property name="default_width">800</property>
<property name="default_height">600</property>
<child type="titlebar">
<object class="GtkHeaderBar" id="headerbar1">
<property name="visible">True</property>
<property name="title">codegui</property>
<property name="spacing">12</property>
<property name="show_close_button">True</property>
<child>
<object class="GtkGrid" id="grid1">
<property name="visible">True</property>
<child>
<object id="buttonUndo"class="GtkMenuToolButton">
<property name="visible">True</property>
<child type="menu">
<object class="GtkMenu" id="menuUndo"/>
</child>
</object>
<packing>
<property name="left_attach">0</property>
<property name="top_attach">0</property>
</packing>
</child>
</object>
</child>
</object>
</child>
</object>
</interface>
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