A similar question has been discussed earlier in this list starting with this post: http://mail.gnome.org/archives/gtk-list/2007-October/msg00003.html > If I use g_timeout_add_full in some callback function ,will it start a > "thread" to do it ? Or just add a new "source" to be handled by > main event loop without thread? It will not start a new thread. It will attach a new source (a timeout-source) to the default main context. The default main context will be handled by the thread which runs a main loop for the default main context, for instance like this: GMainLoop *ml; ml = g_main_loop_new(NULL, FALSE); // NULL means default context g_main_loop_run(ml); (In my understanding there is exactly one _default_ main context per process - please fix me if I am wrong..) > What's the relationship with thread , source and main event loop ? > How should I understand these comments ? In the thread above, the following post may answer your question: http://mail.gnome.org/archives/gtk-list/2007-October/msg00015.html Hope this helps.. Cheers, Oben _______________________________________________ gtk-list mailing list gtk-list@xxxxxxxxx http://mail.gnome.org/mailman/listinfo/gtk-list
