On 04/10/06, Richard Boaz <riboaz@xxxxxxxxx> wrote:
Thank you very much for your answer Richard.... yes i figure that myself a few mins ago... as the pointer value was the same.... then there should be something wrong into my definitions... Thanks for your reply though...
i've modified your code below to demonstrate. but basically, you
must have a known structure defining the pointers elements so that
both routines have access to it the same way.
so, move your data structure definition to the outside, making it a
typedef. then all the routines will know how to access the
individual elements by simply casting the passed pointers.
richard
Thank you very much for your answer Richard.... yes i figure that myself a few mins ago... as the pointer value was the same.... then there should be something wrong into my definitions... Thanks for your reply though...
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