On Fri, 2 Jan 2009, david@xxxxxxx wrote:
On Fri, 2 Jan 2009, david@xxxxxxx wrote:
On Fri, 2 Jan 2009, Jeff King wrote:
The tricky thing here is what is "this line"? Using the line number
isn't right, since it will change based on other content coming in and
out of the file. You can keep drilling down by reblaming parent commits,
but remember that each time you do that you are manually looking at the
content and saying "Oh, this is the line I am still interested in." So I
a script would have to correlate the old version and new version of the
line and realize how to follow the "interesting" thing.
In your case, I think you want to see any commit in Makefile which
changed a line with SUBLEVEL in it. Which is maybe easiest done as:
git log -z -p Makefile |
perl -0ne 'print if /\n[+-]SUBLEVEL/' |
tr '\0' '\n'
and is pretty fast. But obviously we're leveraging some content-specific
knowledge about what's in the Makefile.
Ok, I hacked togeather a quick bash script to try this
<SNIP>
the problem that this has is that line 3 of $COMMIT may not be line 3 of
$COMMIT^, and if they aren't it ends up hunting down the wrong data
either that or I am not understanding the output of git blame properly
(also very possible)
I was misunderstanding git blame
new script is
#!/bin/bash
line=`git blame -n -b -l -L /$1/,+1 -M $2`
echo "-$line"
foundCOMMIT=`echo "$line" |cut -c -40`
foundline=`echo "$line" |cut -c 42- |cut -f 1 -d " "`
while [ "$foundCOMMIT" != " " ] ;do
#git diff -U0 $foundCOMMIT..$foundCOMMIT^ $2
line=`git blame -n -b -l -L $foundline,+1 -M $2 $foundCOMMIT^`
echo "-$line"
foundCOMMIT=`echo "$line" |cut -c -40`
foundline=`echo "$line" |cut -c 42- |cut -f 1 -d " "`
done
this seems to be working for me now.
not quite, it works as long as the line doesn't move in the commit where
it changes.
David Lang
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