On Sat, Oct 18, 2008 at 11:39, René Scharfe <rene.scharfe@xxxxxxxxxxxxxx> wrote:>>> +static struct ref *alloc_ref_with_prefix(const char *prefix, size_t prefixlen,>>> + const char *name)>>> +{>>> + size_t len = strlen(name);>>> + struct ref *ref = xcalloc(1, sizeof(struct ref) + prefixlen + len + 1);>>> + memcpy(ref->name, prefix, prefixlen);>>> + memcpy(ref->name + prefixlen, name, len);>> Where does you \0-terminate the string?>> xcalloc() calls calloc(), which zeroes the memory.So, you write the memory range twice, just for the last \0? Bert>> René>��.n��������+%������w��{.n��������n�r������&��z�ޗ�zf���h���~����������_��+v���)ߣ�m