2008/8/11 Johannes Schindelin <Johannes.Schindelin@xxxxxx>: > Hi, > > On Mon, 11 Aug 2008, Francis Moreau wrote: > >> I found this in git bisect: >> >> printf >&2 'Are you sure [Y/n]? ' >> case "$(read yesno)" in [Nn]*) exit 1 ;; esac >> >> which looks very weird since read(1) returns a status and not the >> string reads from std input. >> >> Am I missing something ? > > Yes. "$()" does not return the status, but the output. But there is no output, since read doesn't print anything... case "$(read yesno; echo $yesno)" in [Nn]*) could work, but looks a bit strange. read yesno; case $yesno in [Nn]*) would be the usual way to do things i think? -- Mikael Magnusson -- To unsubscribe from this list: send the line "unsubscribe git" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
