Hi,
On Sat, 29 Dec 2007, Junio C Hamano wrote:
> Johannes Schindelin <Johannes.Schindelin@xxxxxx> writes:
>
> >> echo "# This is a combination of $COUNT commits."
> >> - sed -n "2,\$p" < "$SQUASH_MSG"
> >> + sed -e 1d -e '2,/^./{
> >> + /^$/d
> >> + }' <"$SQUASH_MSG"
> >
> > If I read this correctly (haven't tested), then _all_ empty lines are
> > removed from the SQUASH_MSG, right? This is not what I want.
>
> That is no what I wanted either.
>
> "1d" removes the "# This is a combination of <$n> commits." from
> the previous round, "2,/^./{ ... }" says apply what's in {} to
> lines from second line to the first non-empty line, and what's
> in {} is to remove empty ones.
Okay, so it removes only the empty lines between the first line and the
next non-empty line.
But if I understood the OP correctly, the problem was a missing newline at
the end of the commit message, no?
Thanks,
Dscho
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