Checks outside of tests are caught at runtime and reported like this:
Assertion failed: (ctx.running), function test_assert, file test-lib.c, line 267.
The assert() call aborts the unit test and doesn't reveal the location
or even the type of the offending check, as test_assert() is called by
all of them.
Handle it like the opposite case, a test without any checks: Don't
abort, but report the location of the actual check, along with a message
explaining the situation. The output for example above becomes:
# BUG: check outside of test at t/helper/test-example-tap.c:75
... and the unit test program continues and indicates the error in its
exit code at the end.
Signed-off-by: René Scharfe <l.s.r@xxxxxx>
---
Changes since v1:
- Set ctx.failed to report the mistake via exit code as well.
t/unit-tests/test-lib.c | 7 ++++++-
1 file changed, 6 insertions(+), 1 deletion(-)
diff --git a/t/unit-tests/test-lib.c b/t/unit-tests/test-lib.c
index 3c513ce59a..989dc758e6 100644
--- a/t/unit-tests/test-lib.c
+++ b/t/unit-tests/test-lib.c
@@ -264,7 +264,12 @@ static void test_todo(void)
int test_assert(const char *location, const char *check, int ok)
{
- assert(ctx.running);
+ if (!ctx.running) {
+ test_msg("BUG: check outside of test at %s",
+ make_relative(location));
+ ctx.failed = 1;
+ return 0;
+ }
if (ctx.result == RESULT_SKIP) {
test_msg("skipping check '%s' at %s", check,
--
2.45.2
