The function `nth_midxed_object_oid()` returns the object ID for a given
object position in the MIDX lexicographic order.
Teach this function to instead operate over the concatenated
lexicographic order defined in an earlier step so that it is able to be
used with incremental MIDXs.
To do this, we need to both (a) adjust the bounds check for the given
'n', as well as record the MIDX-local position after chasing the
`->base_midx` pointer to find the MIDX which contains that object.
Signed-off-by: Taylor Blau <me@xxxxxxxxxxxx>
---
midx.c | 4 +++-
1 file changed, 3 insertions(+), 1 deletion(-)
diff --git a/midx.c b/midx.c
index da5e0bb940..d470a88755 100644
--- a/midx.c
+++ b/midx.c
@@ -337,9 +337,11 @@ struct object_id *nth_midxed_object_oid(struct object_id *oid,
struct multi_pack_index *m,
uint32_t n)
{
- if (n >= m->num_objects)
+ if (n >= m->num_objects + m->num_objects_in_base)
return NULL;
+ n = midx_for_object(&m, n);
+
oidread(oid, m->chunk_oid_lookup + st_mult(m->hash_len, n),
the_repository->hash_algo);
return oid;
--
2.46.0.rc0.94.g9b2aff57b3
