In general when we know a pointer variable is NULL, it's clearer to
explicitely return NULL than to return that variable.
In get_reference() when 'object' is NULL, we already return NULL
when 'revs->exclude_promisor_objects && is_promisor_object(oid)' is
true, but we return 'object' when 'revs->ignore_missing' is true.
Let's make the code clearer and more uniform by also explicitely
returning NULL when 'revs->ignore_missing' is true.
Signed-off-by: Christian Couder <chriscool@xxxxxxxxxxxxx>
---
revision.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/revision.c b/revision.c
index 2424c9bd67..4c5cd7c3ce 100644
--- a/revision.c
+++ b/revision.c
@@ -385,7 +385,7 @@ static struct object *get_reference(struct rev_info *revs, const char *name,
if (!object) {
if (revs->ignore_missing)
- return object;
+ return NULL;
if (revs->exclude_promisor_objects && is_promisor_object(oid))
return NULL;
die("bad object %s", name);
--
2.43.0.496.gd667eb0d7d.dirty
