Jessica Clarke <jrtc27@xxxxxxxxxx> writes: > So, sizeof(X) does not always equal _Alignof(X), even for primitive > types, _Alignof need only be a factor of sizeof. The two are the same > on most architectures, and is a sensible ABI, but the exception is the > m68k case I was referring to above. On m68k, sizeof(long long) == 8, > but _Alignof(long long) == 2 (yes this is a real pain point of its ABI; Ah, thanks. Having a variant of the above explanation in a comment next to the "union within a struct" would help future readers from asking the same question as I asked.
