Re: [PATCH v4 05/10] unpack-trees: fix nested sparse-dir search

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Am 24.08.21 um 23:51 schrieb Derrick Stolee via GitGitGadget:
> From: Derrick Stolee <dstolee@xxxxxxxxxxxxx>
>
> The iterated search in find_cache_entry() was recently modified to
> include a loop that searches backwards for a sparse directory entry that
> matches the given traverse_info and name_entry. However, the string
> comparison failed to actually concatenate those two strings, so this
> failed to find a sparse directory when it was not a top-level directory.
>
> This caused some errors in rare cases where a 'git checkout' spanned a
> diff that modified files within the sparse directory entry, but we could
> not correctly find the entry.
>
> Helped-by: Johannes Schindelin <Johannes.Schindelin@xxxxxx>
> Helped-by: René Scharfe <l.s.r@xxxxxx>
> Signed-off-by: Derrick Stolee <dstolee@xxxxxxxxxxxxx>
> ---
>  unpack-trees.c | 7 +++++--
>  1 file changed, 5 insertions(+), 2 deletions(-)
>
> diff --git a/unpack-trees.c b/unpack-trees.c
> index 5786645f315..47ef0cf4c53 100644
> --- a/unpack-trees.c
> +++ b/unpack-trees.c
> @@ -1255,7 +1255,8 @@ static int sparse_dir_matches_path(const struct cache_entry *ce,
>  static struct cache_entry *find_cache_entry(struct traverse_info *info,
>  					    const struct name_entry *p)
>  {
> -	struct cache_entry *ce;
> +	const char *path;
> +	struct cache_entry *ce = NULL;
                              ^^^^^^^
This added initialization doesn't seem to be needed...

>  	int pos = find_cache_pos(info, p->path, p->pathlen);
>  	struct unpack_trees_options *o = info->data;
>
> @@ -1283,7 +1284,9 @@ static struct cache_entry *find_cache_entry(struct traverse_info *info,
>  	while (pos >= 0) {
>  		ce = o->src_index->cache[pos];

... because ce is set here before it's used.

>
> -		if (strncmp(ce->name, p->path, p->pathlen))
> +		if (!skip_prefix(ce->name, info->traverse_path, &path) ||
> +		    strncmp(path, p->path, p->pathlen) ||
> +		    path[p->pathlen] != '/')
>  			return NULL;
>
>  		if (S_ISSPARSEDIR(ce->ce_mode) &&
>




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