There's a safety check to make sure branch->refname is not different
from branch->merge[0]->src, otherwise we die().
Therefore we always push to branch->refname.
Suggestions-by: Elijah Newren <newren@xxxxxxxxx>
Signed-off-by: Felipe Contreras <felipe.contreras@xxxxxxxxx>
---
builtin/push.c | 10 ++--------
1 file changed, 2 insertions(+), 8 deletions(-)
diff --git a/builtin/push.c b/builtin/push.c
index 9c807ed707..73fe083682 100644
--- a/builtin/push.c
+++ b/builtin/push.c
@@ -225,14 +225,10 @@ static void setup_push_current(struct remote *remote, struct branch *branch)
static void setup_push_simple(struct remote *remote, struct branch *branch, int triangular)
{
- const char *dst;
-
if (!branch)
die(_(message_detached_head_die), remote->name);
- if (triangular) {
- dst = branch->refname;
- } else {
+ if (!triangular) {
if (!branch->merge_nr || !branch->merge || !branch->remote_name)
die(_("The current branch %s has no upstream branch.\n"
"To push the current branch and set the remote as upstream, use\n"
@@ -248,10 +244,8 @@ static void setup_push_simple(struct remote *remote, struct branch *branch, int
/* Additional safety */
if (strcmp(branch->refname, branch->merge[0]->src))
die_push_simple(branch, remote);
-
- dst = branch->merge[0]->src;
}
- refspec_appendf(&rs, "%s:%s", branch->refname, dst);
+ refspec_appendf(&rs, "%s:%s", branch->refname, branch->refname);
}
static int is_workflow_triangular(struct remote *remote)
--
2.32.0.rc0
