Re: [BUG] Regression in 'git mergetool --tool-help'

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Hi everyone,

Le 2020-12-20 à 11:23, René Scharfe a écrit :
Am 20.12.20 um 11:28 schrieb Johannes Sixt:
Am 20.12.20 um 03:13 schrieb Philippe Blain:
Thanks for both answers. Felipe's solution does the trick, but Junio's
does not;
it seems we do have to have a newline there. The following also works,
and I think
is portable:

diff --git i/git-mergetool--lib.sh w/git-mergetool--lib.sh
index 2defef28cd..6f03975493 100644
--- i/git-mergetool--lib.sh
+++ w/git-mergetool--lib.sh
@@ -46,7 +46,7 @@ show_tool_names () {
          while read scriptname
          do
              setup_tool "$scriptname" 2>/dev/null
-            variants="$variants$(list_tool_variants)\n"
+            variants="$(echo "$variants" && list_tool_variants)"
          done
          variants="$(echo "$variants" | sort | uniq)"

I figured out what was different between the different Ubuntu versions I
was testing:
the Ubuntu 14 and 18 systems have Bash as /bin/sh, but my Ubuntu 20 system
has /usr/bin/dash as /bin/sh (the default for Ubuntu these days).

I'll try to send a formal patch with the diff above, time permitting...

If possible, please do not use sub-processes like in your suggested
patch. How about

		variants="$variants
$(list_tool_variants)"

This still starts a subshell in the last line.  How about something
like this?

diff --git a/git-mergetool--lib.sh b/git-mergetool--lib.sh
index 7225abd811..79d5ed1fa9 100644
--- a/git-mergetool--lib.sh
+++ b/git-mergetool--lib.sh
@@ -46,11 +46,9 @@ show_tool_names () {
  		while read scriptname
  		do
  			setup_tool "$scriptname" 2>/dev/null
-			variants="$variants$(list_tool_variants)\n"
-		done
-		variants="$(echo "$variants" | sort | uniq)"
-
-		for toolname in $variants
+			list_tool_variants
+		done | sort | uniq |
+		while read toolname
  		do
  			if setup_tool "$toolname" 2>/dev/null &&
  				(eval "$condition" "$toolname")

It requires setup_tool to be silent, though.


Thanks René and Johannes for two additional suggestions; both work correctly.
Junio, I retried yours and verified my quoting and I confirm it does not work.

I think I prefer René's suggestion.

Thanks all,

Philippe.



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