The comment makes it seem as if the condition is the other way around.
The exception is when the oid is null, so check for that.
Signed-off-by: Felipe Contreras <felipe.contreras@xxxxxxxxx>
---
builtin/fetch.c | 16 +++++++++-------
1 file changed, 9 insertions(+), 7 deletions(-)
diff --git a/builtin/fetch.c b/builtin/fetch.c
index 8af5e319f1..9dc551551e 100644
--- a/builtin/fetch.c
+++ b/builtin/fetch.c
@@ -367,19 +367,21 @@ static void find_non_local_tags(const struct ref *refs,
*/
for_each_string_list_item(remote_ref_item, &remote_refs_list) {
const char *refname = remote_ref_item->string;
+ struct ref *rm;
item = hashmap_get_from_hash(&remote_refs, strhash(refname), refname);
if (!item)
BUG("unseen remote ref?");
/* Unless we have already decided to ignore this item... */
- if (!is_null_oid(&item->oid)) {
- struct ref *rm = alloc_ref(item->refname);
- rm->peer_ref = alloc_ref(item->refname);
- oidcpy(&rm->old_oid, &item->oid);
- **tail = rm;
- *tail = &rm->next;
- }
+ if (is_null_oid(&item->oid))
+ continue;
+
+ rm = alloc_ref(item->refname);
+ rm->peer_ref = alloc_ref(item->refname);
+ oidcpy(&rm->old_oid, &item->oid);
+ **tail = rm;
+ *tail = &rm->next;
}
hashmap_free(&remote_refs, 1);
string_list_clear(&remote_refs_list, 0);
--
2.21.0
