Thanks for answer, git checkout -f -b "branch_name" gives me " Fatal: A branch named 'branch_name' already exists." I understand that here the checkout is force, but not the branch creation. The opposite option order doesn't work: git checkout -b -f "branch_name" gives me "Fatal: '-f' is not a valid branch name." Once again sorry if this is expected behavior. [For clarity, I'm trying to move a branch and checkout it with one command.] Regards, Joris -----Message d'origine----- De : Randall S. Becker <rsbecker@xxxxxxxxxxxxx> Envoyé : lundi 28 janvier 2019 15:12 À : COLLOMB Joris -EXT <joris.collomb-ext@xxxxxxxxxxxxxxx>; git@xxxxxxxxxxxxxxx Objet : RE: Git checkout multiple options issue On January 28, 2019 8:25, COLLOMB Joris wrote: > git checkout -fb "branch_name" > (force branch creation and checkout it) > > doesn't work (even if option a separated). > > I don't know if this is consider as an issue, but here it is. I think you might mean (which works on every platform I have): git checkout -f -b "branch_name" There is no provision for aggregating options into one. -fb (invalid) is not the same as -f -b (valid). Regards, Randall -- Brief whoami: NonStop developer since approximately 211288444200000000 UNIX developer since approximately 421664400 -- In my real life, I talk too much. ________________________________ CONFIDENTIALITY : This e-mail and any attachments are confidential and may be privileged. If you are not a named recipient, please notify the sender immediately and do not disclose the contents to another person, use it for any purpose or store or copy the information in any medium.
