Junio C Hamano <gitster@xxxxxxxxx> writes:
> It would make it even easier to follow if you did
>
> if (*arg == '/') {
> opt2 = ...;
> arg++;
> } else {
Oops, this should read "else if (!*arg) {", of course, to match the
original. Sorry for the noise.
> opt2 = 0;
> }
And then we'd want a blank line here to make it clear that the
previous if/else cascade has finished, and the error checking we see
next is not part of it.
> if (*arg)
> return error(...);
>
> It makes it clear that opt2==0 means <n> form and not <n>/<m> form,
> by having an explicit assignment while we parse what *arg points at,
> without the initialization to 0 in the variable definition.
