Re: Regression `git checkout $rev -b branch` while in a `--no-checkout` clone does not check out files

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On Thu, Jan 3, 2019 at 1:51 PM Junio C Hamano <gitster@xxxxxxxxx> wrote:
>
> Anthony Sottile <asottile@xxxxxxxxx> writes:
>
> > On Thu, Jan 3, 2019 at 12:26 PM Junio C Hamano <gitster@xxxxxxxxx> wrote:
> >> A "fix" to Ben's optimization for this particular case should be
> >> fairly straight-forward.  I think we have a special case in the
> >> checkout codepath for an initial checkout and disable "carry forward
> >> the fact that the user wanted all the paths removed", so it would be
> >> the matter of adding yet another condition (is_cache_unborn(), which
> >> is used to set topts.initial_checkout) to the large collection of
> >> conditions in skip_merge_working_tree().
> >
> > I think it might be simpler than that even -- the optimization treats
> > the following as equivalent when the current checked out revision is
> > deadbeef (even if the index / worktree differ), when before they were
> > not:
> >
> > - git checkout -b newbranch
> > - git checkout deadbeef -b newbranch
> >
> > If a revision is specified on the commandline it should be checked out.
>
> If it were to be a "fix", the exact same command line as people used
> to be able to use, i.e. "git checkout -b newbranch", should be made
> to do what it used to do.
>
> Forcing users to use a different command to workaround the bug is
> not a usable "fix".  If we want a working workaround, you can tell
> your users to use
>
>     git reset --hard HEAD && git checkout -b newbranch
>
> and that would already work without any code change ;-).
>
>

oh wow, I didn't realize `git checkout -b newbranch` also used to
reset the `--no-checkout` state, yeah you're right the optimization is
way more problematic than I had considered.

I'm working around by not using `--no-checkout` personally

Anthony



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