Convert 'match_explicit_refs()' to take a 'struct refspec' as a
parameter instead of a list of 'struct refspec_item'.
Signed-off-by: Brandon Williams <bmwill@xxxxxxxxxx>
---
remote.c | 9 ++++-----
1 file changed, 4 insertions(+), 5 deletions(-)
diff --git a/remote.c b/remote.c
index 9eb79ea19..84dda3fd0 100644
--- a/remote.c
+++ b/remote.c
@@ -1073,12 +1073,11 @@ static int match_explicit(struct ref *src, struct ref *dst,
}
static int match_explicit_refs(struct ref *src, struct ref *dst,
- struct ref ***dst_tail, struct refspec_item *rs,
- int rs_nr)
+ struct ref ***dst_tail, struct refspec *rs)
{
int i, errs;
- for (i = errs = 0; i < rs_nr; i++)
- errs += match_explicit(src, dst, dst_tail, &rs[i]);
+ for (i = errs = 0; i < rs->nr; i++)
+ errs += match_explicit(src, dst, dst_tail, &rs->items[i]);
return errs;
}
@@ -1302,7 +1301,7 @@ int match_push_refs(struct ref *src, struct ref **dst,
refspec = default_refspec;
}
refspec_appendn(&rs, refspec, nr_refspec);
- errs = match_explicit_refs(src, *dst, &dst_tail, rs.items, rs.nr);
+ errs = match_explicit_refs(src, *dst, &dst_tail, &rs);
/* pick the remainder */
for (ref = src; ref; ref = ref->next) {
--
2.17.0.441.gb46fe60e1d-goog
