Re: [PATCH v4 1/4] Makefile: generate Perl header from template file

[Johannes Sixt <j6t@xxxxxxxx>]

Am 29.11.2017 um 16:56 schrieb Dan Jacques:
> @@ -1989,6 +1986,15 @@ GIT-PERL-DEFINES: FORCE
>   		echo "$$FLAGS" >$@; \
>   	    fi
>   
> +GIT-PERL-HEADER: $(PERL_HEADER_TEMPLATE) GIT-PERL-DEFINES perl/perl.mak Makefile
> +	$(QUIET_GEN)$(RM) $@ && \
> +	INSTLIBDIR=`MAKEFLAGS= $(MAKE) -C perl -s --no-print-directory instlibdir` && \
> +	INSTLIBDIR_EXTRA='$(PERLLIB_EXTRA_SQ)' && \
> +	INSTLIBDIR="$$INSTLIBDIR$${INSTLIBDIR_EXTRA:+:$$INSTLIBDIR_EXTRA}" && \
> +	sed -e 's=@@PATHSEP@@=$(pathsep)=g' \

This doesn't work, unfortunately. When $(pathsep) is ';', we get an 
incomplete sed expression because ';' is also a command separator in the 
sed language.

> +	    -e 's=@@INSTLIBDIR@@='$$INSTLIBDIR'=g' \
> +	    $< >$@+ && \
> +	mv $@+ $@
>   
>   .PHONY: gitweb
>   gitweb:

-- Hannes