Re: [PATCH 11/11] refs: split and make get_*_ref_store() public API

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>
> +/*
> + * Return the ref_store instance for the specified submodule. For the
> + * main repository, use submodule==NULL; such a call cannot fail.

So now we have both a get_main as well as a get_submodule function,
but the submodule function can return the main as well?

I'd rather see this as a BUG; or asking another way:
What is the difference between get_submodule_ref_store(NULL)
and get_main_ref_store() ?

As you went through all call sites (by renaming the function), we'd
be able to tell that there is no caller with NULL, or is it?

Stefan

> For
> + * a submodule, the submodule must exist and be a nonbare repository,
> + * otherwise return NULL. If the requested reference store has not yet
> + * been initialized, initialize it first.
> + *
> + * For backwards compatibility, submodule=="" is treated the same as
> + * submodule==NULL.
> + */
> +struct ref_store *get_submodule_ref_store(const char *submodule);
> +struct ref_store *get_main_ref_store(void);



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