Junio C Hamano <gitster@xxxxxxxxx> writes:
> + while (url_len && pat_len) {
> + const char *url_next = end_of_token(url, '.', url_len);
> + const char *pat_next = end_of_token(pat, '.', pat_len);
> + ...
> }
>
> + return 1;
Embarrassing. The last one must be "have they both run out?" i.e.
return (!url_len && !pat_len);