Hello,
Is it expected for check-ignore to output included files (using a "!"
prefix)?
Steps to reproduce:
git init foo
cd foo
touch bar
echo '/bar\n!/bar' > .gitignore
git add bar .gitignore
git commit -mbar
git check-ignore --verbose --no-index bar
Actual behavior:
.gitignore:2:!/bar bar
exit code = 0
Expected behavior:
no output
exit code = 1
I tested with the next branch, which is currently at
8a191e187a9dca3d786c0197f9610e627b4f4137.
The man page of check-ignore says:
« For each pathname [...], check whether the file is excluded by
.gitignore [...] and output the path if it is excluded. »
and:
« If the pattern contained a ! prefix or / suffix, it will be
preserved in the output. »
The man page of gitignore says:
« An optional prefix "!" which negates the pattern; any matching file
excluded by a previous pattern will become included again. »
I am not sure how I should understand this situation.
Best regards,
Julien��.n��������+%������w��{.n��������n�r������&��z�ޗ�zf���h���~����������_��+v���)ߣ�