On Wed, May 11, 2016 at 2:36 AM, Eric Sunshine <sunshine@xxxxxxxxxxxxxx> wrote:
> On Tue, May 10, 2016 at 10:15 AM, Nguyễn Thái Ngọc Duy
> <pclouds@xxxxxxxxx> wrote:
>> The use case is keep some worktree and discard the rest of the worktree
>> list.
>
> So, you're saying that rather than a client freeing the entire
> worktree list like this:
>
> free_worktrees(worktrees);
>
> it might instead want to keep some element ('n') and free all others
> plus the list itself, like this:
>
> struct worktree *keep = worktrees[n];
> struct worktree **p = worktrees;
> for (; *p; p++)
> if (*p != keep)
> clear_worktree(*p);
> free(worktrees);
>
> Is that correct?
>
> If so, then doesn't this require the client to have far too intimate
> knowledge of the internals of free_worktrees(). Or, was your idea that
> the client would simply leak the 'worktrees' array after freeing the
> unwanted elements?
>
> In either case, a cleaner approach might be to provide a function for
> copying a worktree element. Perhaps:
>
> struct worktree *copy_worktree(const struct worktree *);
Of course, you'd still need a clear_worktree() or free_worktree()
function to dispose of the copy.
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