Jeff King <peff@xxxxxxxx> writes:
> +/*
> + * We anonymize each component of a path individually,
> + * so that paths a/b and a/c will share a common root.
> + * The paths are cached via anonymize_mem so that repeated
> + * lookups for "a" will yield the same value.
> + */
> +static void anonymize_path(struct strbuf *out, const char *path,
> + struct hashmap *map,
> + char *(*generate)(const char *, size_t *))
> +{
> + while (*path) {
> + const char *end_of_component = strchrnul(path, '/');
> + size_t len = end_of_component - path;
> + const char *c = anonymize_mem(map, generate, path, &len);
> + strbuf_add(out, c, len);
> + path = end_of_component;
> + if (*path)
> + strbuf_addch(out, *path++);
> + }
> +}
Do two paths sort the same way before and after anonymisation? For
example, if generate() works as a simple substitution, it should map
a character that sorts before (or after) '/' with another that also
sorts before (or after) '/' for us to be able to diagnose an error
that comes from D/F sort order confusion.
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