Jeff King <peff@xxxxxxxx> writes:
> On Wed, Apr 23, 2014 at 12:12:14PM -0700, Junio C Hamano wrote:
>
>> > +ulimit_stack="ulimit -s 64"
>> > +test_lazy_prereq ULIMIT 'bash -c "'"$ulimit_stack"'"'
>>
>> With this implementaion, ULIMIT implies bash, and we use bash that
>> appears on user's PATH that may not be the one the user chose to run
>> git with. Can't we fix both of them by using $SHELL_PATH?
>
> I don't think so. The point is that we _must_ use bash here, not any
> POSIX shell.
Sorry, but I do not understand. Isn't what you want "any POSIX
shell with 'ulimit -s 64' supported"?
$ dash -c 'ulimit -s && ulimit -s 64 && ulimit -s'
8192
64
> We want to run "some bash" if we can. We may pick a bash on the user's
> PATH that is not what they put into $SHELL_PATH, but that should be
> relatively rare. And the consequence is that either that bash works fine
> and we run the test, or it does not, and we skip the test.
>
>> How about doing it along this line instead?
>>
>> run_with_limited_stack () {
>> "$SHELL_PATH" -c "ulimit -s 64 && $*"
>> }
>>
>> test_lazy_prereq ULIMIT "run_with_limited_stack true"
>
> That's a much more direct test. I like it (aside from the $SHELL_PATH
> thing as described above).
Still puzzled.
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