Re: [PATCH v3][GSOC] fsck: use bitwise-or assignment operator to set flag

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Junio and Eric,

Thank you for the reviews and helpful advice.
I should have read more past commit messages before send patch.


Regards,


2014-03-21 3:20 GMT+09:00 Junio C Hamano <gitster@xxxxxxxxx>:
> Hiroyuki Sano <sh19910711@xxxxxxxxx> writes:
>
>> fsck_tree() has two different ways to set a flag,
>> which are the followings:
>>
>>   1. Using a if-statement that guards assignment.
>>
>>   2. Using a bitwise-or assignment operator.
>>
>> Currently, many with the former way,
>> and one with the latter way.
>>
>> In this patch, unify them to the latter way,
>> because it makes the code shorter and easier to read,
>> and it is brief and to the point.
>
> Two issues:
>
>  * "In this patch," is redundant.
>
>  * "it is brief and to the point" are equally applicable to both
>    styles, so that is not a *reason* to choose one over the other.
>
> If a condition were *not* brief and to the point, then a rewrite to
> the latter style will make the resulting code worse:
>
>         if (a very complex condition
>             that potentially have to consume a
>             lot of brain-cycles to understand) {
>                 has_that_condition = 1;
>         }
>
> is a lot easier to extend than
>
>         has_that_condition = (a very complex condition
>                               that potentially have to consume a
>                               lot of brain-cycles to understand);
>
> because it is a lot more likely that we would need to later extend
> such a complex condition is more likely than a simple singleton
> condition, and we could end up with
>
>         if (a very complex condition
>             that potentially have to consume a
>             lot of brain-cycles to understand) {
>                 futher computation to check if
>                 the condition really holds
>                 will be added here later
>                 if (does that condition really hold true?)
>                         has_that_condition = 1;
>         }
>
>
> which may be harder to express in the latter form.
>
> In other words, "it is brief and to the point" merely _allows_ these
> statements to be expressed in the latter form; it does not say
> anything about which is better between the former and the latter.
>
>> Signed-off-by: Hiroyuki Sano <sh19910711@xxxxxxxxx>
>> ---
>>  fsck.c | 18 ++++++------------
>>  1 file changed, 6 insertions(+), 12 deletions(-)
>>
>> diff --git a/fsck.c b/fsck.c
>> index b3022ad..abed62b 100644
>> --- a/fsck.c
>> +++ b/fsck.c
>> @@ -165,18 +165,12 @@ static int fsck_tree(struct tree *item, int strict, fsck_error error_func)
>>
>>               sha1 = tree_entry_extract(&desc, &name, &mode);
>>
>> -             if (is_null_sha1(sha1))
>> -                     has_null_sha1 = 1;
>> -             if (strchr(name, '/'))
>> -                     has_full_path = 1;
>> -             if (!*name)
>> -                     has_empty_name = 1;
>> -             if (!strcmp(name, "."))
>> -                     has_dot = 1;
>> -             if (!strcmp(name, ".."))
>> -                     has_dotdot = 1;
>> -             if (!strcmp(name, ".git"))
>> -                     has_dotgit = 1;
>> +             has_null_sha1 |= is_null_sha1(sha1);
>> +             has_full_path |= !!strchr(name, '/');
>> +             has_empty_name |= !*name;
>> +             has_dot |= !strcmp(name, ".");
>> +             has_dotdot |= !strcmp(name, "..");
>> +             has_dotgit |= !strcmp(name, ".git");
>>               has_zero_pad |= *(char *)desc.buffer == '0';
>>               update_tree_entry(&desc);



-- 
Hiroyuki Sano
sh19910711@xxxxxxxxx
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