Re: git checkout creates strange '(null)'-branch

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Johannes Sixt <j.sixt@xxxxxxxxxxxxx> writes:

> Am 5/8/2012 13:24, schrieb Erik Faye-Lund:
>> +		git show-ref | !grep "(null)"
> ...
>> Now, doing this doesn't make my test above pass,
>
> It is unlikely to pass if you used this test script literally, because
>
>    $ !grep
>    !grep: command not found
>
> "!" is not an operator in a shell script. Insert a space.

Good eyes.  Also wouldn't it be a bit pointless to grep for (null) in the
first place?  It comes only because a particular implementation of
vsnprintf() happens to emit it when asked to turn a NULL pointer into a
string, and on other platforms it is allowed to segfault.
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