2012/3/5 Junio C Hamano <gitster@xxxxxxxxx>:
> This is a tangent and I am just showing aloud my ignorance, but I wonder
> if there is a reasonably generic and "best current practice" way to
> structure code to show an enumeration in human languages, for example,
>
> A, B, C and D.
>
> in an easier-to-translate way.
>
> I suspect that it might be sufficiently generic if we can make it possible
> to allow the first and the last inter-word-separation and the token after
> all the items to be different from other inter-word-separation tokens.
>
> E.g. in English, the first one and all the "other" are ", ", the last
> inter-word token is " and ", and the token at the very end is ".". In
> Japanese some translators may want to say "AやBとCとD。", meaning the
> first one is "や", "。" is used at the very end, and all the others may be
> "と".
I write a function for this.
/*
* Make list of items easy for l10n translation.
*
* 1. Input list of items one by one through the 2nd argument,
* but leave the 1st argument as NULL.
*
* 2. Get the output joint string from the 1st argument.
*
* According to the number of items input. The joint string maybe:
*
* a
* a and b
* a, b and c
* a, b, c and d
*
*/
#define MAX_L10N_LIST_ITEMS_COUNT 128
void append_l10n_list_items(struct strbuf *ret, const char *item)
{
static const char **itemlist = NULL;
static int count = 0;
int i = 0;
if (itemlist == NULL)
itemlist = xmalloc(MAX_L10N_LIST_ITEMS_COUNT * sizeof(char*));
if(item != NULL && count < MAX_L10N_LIST_ITEMS_COUNT )
itemlist[count++] = item;
if (ret != NULL) {
if (count == 1) {
strbuf_addstr(ret, itemlist[0]);
}
else if (count == 2) {
strbuf_addf(ret, _("%s and %s"), itemlist[0], itemlist[1]);
}
else if (count > 2) {
strbuf_addf(ret, _("%s, "), itemlist[0]);
for (i=1; i<count-2; i++) {
strbuf_addstr(ret, itemlist[i]);
strbuf_addstr(ret, _(", "));
}
strbuf_addf(ret, _("%s and %s"), itemlist[count-2],
itemlist[count-1]);
}
free(itemlist);
itemlist = NULL;
count = 0;
}
}
...
strbuf_addstr(&extra, " ("))
if (a)
append_l10n_list_items(NULL, _("msg a"));
if (b)
append_l10n_list_items(NULL, _("msg b"));
if (c)
append_l10n_list_items(NULL, _("msg c"));
append_l10n_list_items(&extra, NULL);
...
--
Jiang Xin
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