Re: [PATCH] git-completion: workaround zsh COMPREPLY bug

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On Wed, Jan 25, 2012 at 9:41 AM, Matthieu Moy
<Matthieu.Moy@xxxxxxxxxxxxxxx> wrote:
> Felipe Contreras <felipe.contreras@xxxxxxxxx> writes:
>
>> The simplest and most generic solution is to hide all the changes we do
>> to IFS, so that "foo \nbar " is recognized by zsh as "foo bar". This
>> works on versions of git before and after the introduction of
>> __gitcomp_nl (a31e626), and versions of zsh before and after 4.3.12.
> [...]
>> +
>> +             # another workaround for zsh because it would quote spaces in
>> +             # the COMPREPLY array if IFS doesn't contain spaces
>> +             typeset -h IFS
>
> No time to test right now, but is this not going to
>
> 1) leave IFS as hidden even outside the completion script, possibly
> affecting unrelated scripts that would need to set IFS as local and keep
> its special effect?

What special effect?

Unrelated scripts can still set IFS as local.

You can test this:

---
#!/bin/sh

if [[ -n ${ZSH_VERSION-} ]]; then
    autoload -U +X bashcompinit && bashcompinit
fi

_foo()
{
    typeset -h IFS
    local cur="${COMP_WORDS[COMP_CWORD]}"
    local IFS=$'\n'
    w[0]='first '
    w[1]='second and space '
    w[2]='third\\ quoted\\ space '
    ./test1 >> /tmp/t1.txt
    COMPREPLY=( $(compgen -W "${w[*]}" -- $cur) )
}
complete -o nospace -F _foo foo
---

test1:
---
#!/bin/sh

test1() {
	local IFS=$'\n'
	w=( $(echo -e "foo \nbar"))
	echo "test1: 0:'${w[0]}' 1:'${w[1]}'"
}

test1

w=( $(echo -e "foo \nbar"))
echo "test2: 0:'${w[0]}' 1:'${w[1]}'"
---

The result in /tmp/t1.txt would be:
test1: 0:'foo ' 1:'bar'
test2: 0:'foo' 1:'bar'

Regardless of whether you use typeset -h or not.

> 2) break cases where strings are to be split on \n only (e.g. see
> "foo bar\nboz" as three possible completions "foo", "bar", "boz" instead
> of "foo bar" and "boz"?

Those cases are already broken, which is what I reported to the zsh
mailing list. You would get "foo\ bar" and "boz", and that's after
4.3.12; before, compgen -W would still break the completions in 3,
because they did 'results+=( $words )', instead of 'results+=(
"$words" )'.

Cheers.

-- 
Felipe Contreras
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