Thanks four your answer, it was really great help (cleared up everything)!
Best regards,
Ákos Tajti
2011.09.06. 17:24 keltezéssel, mfwitten@xxxxxxxxx írta:
On Tue, 06 Sep 2011 13:44:50 +0200, Tajti wrote:
what does the right-only option of git-log actually do? The manual is
not too verbose about it.
The documentation is indeed a bit messy, so let me rearrange it for you.
From `git help rev-parse':
r1...r2 is called symmetric difference of r1 and r2 and is
defined as `r1 r2 --not $(git merge-base --all r1 r2)'. It is
the set of commits that are reachable from either one of r1 or
r2 but not from both.
Then we have this from `git help log':
--left-right
Mark which side of a symmetric diff a commit is reachable
from. Commits from the left side [(r1 above)] are prefixed with
< and those from the right [(r2 above)] with>...
which should explain what `<' and `>' mean in the following from
`git help log':
--left-only, --right-only
List only commits on the respective side of a symmetric
range, i.e. only those which would be marked< resp.> by
--left-right.
This is probably most useful with the following option, described
in `git help log':
--cherry-pick
Omit any commit that introduces the same change as another
commit on the "other side" when the set of commits are
limited with symmetric difference.
...
For example, --cherry-pick --right-only A...B omits those
commits from B which are in A or are patch-equivalent to a
commit in A. In other words, this lists the + commits from
git cherry A B. More precisely, --cherry-pick --right-only
--no-merges gives the exact list.
That is, you often run into multiple commit objects that are unique
because of, say, differing commit dates, but that actually introduce
the same change to the source; this combination of options is helpful
in weeding out commits that introduce the same change.
If you're still confused, don't hesitate to poke the list some more;
the documentation is quite lacking over all topics, so don't feel
stupid.
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