On Thu, Dec 9, 2010 at 2:51 AM, Jakub Narebski <jnareb@xxxxxxxxx> wrote:
> Dnia Åroda 8. grudnia 2010 19:06, Jonathan Nieder napisaÅ:
>> Nguyán ThÃi Ngác Duy wrote:
>>
>> > Let's start off from where the previous discussion [1] stopped. People
>> > seem to agree ref^{/regex} is a good choice. But we have not come to
>> > conclusion how to specify the count yet. Possible suggestions are
>> >
>> > Â- ref^{/foo}2
>> > Â- ref^{2/foo}
>> > Â- ref^{:2/foo}
>> > Â- ref^{2nd/foo}
>>
>> How about
>>
>> Â Â Â ref^{/foo}^^{/foo}
>>
>> ?
>
> I'll assume that there is invisible ";)" emoticon here.
>
>
> First, it would be ref^{/foo}^@^{/foo}, otherwise you would follow only
> first parent.
>
> Second, consider ref^{:nth(10)/foo} in your workaround...
Maybe we should generalize this to apply to all operators. Currently
foo~3 is expanded to foo^^^. How about ~~X (or xN) denote repeat the
last operator N times? For example, HEAD^2x3 => HEAD^2^2^2,
HEAD^{/foo}x3 => HEAD^{/foo}^{/foo}^{/foo}.
--
Duy
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