Dennis Stosberg <dennis@xxxxxxxxxxxx> wrote:
> + echocheck "for perl"
> + if test -z "$_perl" ; then
> + _perl=`which perl`
> + test "$_perl" || die "cannot find path to perl"
> + fi
> + echores "$_perl"
"which" isn't portable. On SunOS 5.9 "which foo" prints error message to
stdout and returns 0. I use this in my own configure scripts:
path_find()
{
if test -x "$1"
then
echo "$1"
return 0
fi
for i in `echo $PATH | sed 's/:/ /g'`
do
if test -x "$i/$1"
then
echo "$i/$1"
return 0
fi
done
return 1
}
--
http://onion.dynserv.net/~timo/
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