Re: Re: int8_t outputs char via <iostream>

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Hello,
I would argue the way it works currently is dangerous and asks for issues.

Let me further demonstrate the problem with examples;

1. For <iostream> demonstration 1
/*-------------------------------------------------*/

#include <cstdint>
#include <iostream>

int main()
{
    std::int8_t myInt{65};
    std::cout << "Takes ASCII char " << myInt << '\n';
    std::cout << "(static_cast): " << static_cast<int>(myInt) << '\n';
    std::cout << "(int): " << (int)myInt << '\n';

    return 0;
}
// First prints the ASCII character for 65, which is "A"
// (int) and static_cast print 65 correctly.
// The programmer learns to use (int) to print out int8_t

/*-------------------------------------------------*/
2. <iostream> demonstration 2
/*-------------------------------------------------*/

#include <cstdint>
#include <iostream>

int main()
{
    std::cout << "Enter a number between 0 and 127: ";
    std::int8_t myInt{};
    std::cin >> myInt;
    std::cout << "You entered (no cast): " << myInt << '\n';
    std::cout << "You entered (static_cast): " << static_cast<int>(myInt)
<< '\n';
    std::cout << "You entered ( (int) ): " << (int)myInt << '\n';
    return 0;
}

// *User input:* 35
// You entered: 3 // this is the first char given
onlly. The second one is ignored.
// You entered (static_cast): 51 // this is when the programmer assumes
(int) or static_cast<int> should be used
// You entered ( (int )): 51 // 51 is the ASCII number for '3' .


/*-------------------------------------------------*/
3. <cstdio> demonstration 3
/*-------------------------------------------------*/

#include <iostream>
#include <cstdint>
#include <cstdio>
int main()
{
    std::int8_t num{};
    std::scanf("%hhd", &num); // Read the number and
store it in num
    std::printf("%d this for cstdio.h\n", num); // Print the value of num
    std::cout << sizeof(num) * 8;
    return 0;
}
//*User input*: 100
// prints correctly 100
// size is still int8_t.



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