Hello,
With <iostream> int8_t prints out char according to ascii number. Similarly
it reads a single char, which cannot be static converted. The compiler
gives no warning whatsoever. But when <cstdio> is used with scanf %hhd and
printf %d it works perfectly. Is this really the intended <iostream>
functioning? In Rust i8 and C <stdio.h> int8 works fine, too.
#include <iostream>
#include <cstdint>
int main()
{
std::int8_t myInt{65};
myInt += 1;
std::cout << myInt;
}
Guess what this returns?
Character "B".
int main()
{
std::int8_t myInt{};
std::cin >> myInt;
std::cout << myInt;
}
This will also read a character, and
print the characters ascii value.
So if I give it 3, it read it as '3', and prints out 51.
The compiler gives no warning of this whatsoever with the flags:
"-std=c++20",
"-pedantic-errors",
"-Wall",
"-Wpedantic",
"-Wshadow",
"-Wcast-align",
"-Wlogical-op",
"-Wno-unused-parameter",
"-Weffc++",
"-Wextra",
"-Wconversion",
"-Wsign-conversion".
It does seem like a mistake to have `signed char` and `unsigned char`
display as characters rather than numbers, since `char` is a distinct type.
And so `char` could display as a character and the other two as integers.
Wish you can change this, or at least have a warning, because <iostream>
functions fine for higher bitted integers.
Thanks.
OE
