On 8/10/23 09:45, John Scott via Gcc-help wrote:
This is a C99 feature. Essentially, since arrays are implicitly converted to pointers when passed to functions, this: void foo(char s[restrict]); is equivalent to this: void foo(char *restrict s);
Thank you. I wasn't familiar with the "array" version of the syntax.
Note that the [.size] notation is neither a C feature nor a GCC extension; it's a notational convenience used in the Linux man pages. The proper way to declare a function that takes an array of a specified size is to use the static qualifier like so: void foo(size_t array_size, char s[static array_size]); which specifies that s must point to at least array_size elements when the function is called.
I can't believe that I didn't know about this before now.
If the size argument needs to come after the array parameter, then that's what the GCC extension of being able to forward declare parameters is for: void foo(size_t size; char [static size], size_t size);
Cool! Thanks again! -- ======================================================================== Google Where SkyNet meets Idiocracy ========================================================================
