Hello Mr. Jonathan Wakely
Basically, my program only creates a Base class to be inherited, and only uses the Derived1 class in the main program. What is the purpose of the D0 destructor variant that G++ generates?
It is clear that the content of the ~Base() function, which is
cout << "Base Destructor called\n";
, is still executed.
Thank you for your support
Best regards,
Sy Nguyen
________________________________
From: Jonathan Wakely <jwakely.gcc@xxxxxxxxx>
Sent: Thursday, March 2, 2023 11:26 PM
To: Nguyen Duc Sy <sy.nguyen-duc@xxxxxxxxxxxxxx>
Cc: gcc-help@xxxxxxxxxxx <gcc-help@xxxxxxxxxxx>
Subject: Re: [NEED HELP][GCOV] uncoverage virtual destructor
On Thu, 2 Mar 2023 at 12:43, Nguyen Duc Sy wrote:
> but I don't understand why this line is uncovered:
> function _ZN4BaseD0Ev called 0 returned 0% blocks executed 0%
> #####: 11: virtual ~Base(){
> -: 12: cout << "Base Destructor called\n";
> #####: 13: }
>
> Could this be a bug in G++/Gcov?
No, your program never uses the D0 destructor variant. Try:
Base* b = new Base();
delete b;
