Respected Sir/Madam, I have been working on this issue bug 93432 ( https://gcc.gnu.org/bugzilla/show_bug.cgi?id=93432) and tried out few more permutations of the uninitialized variables in the test code. When I compile and run the test code the output is always some garbage value due to the returning of uninitialized variable as mentioned in the comments. 1.I tried removing the continue ,even then it does not give a warning for both clang and gcc.I have used -Wextra ,-Wall,-Wuninitialized,-Winit-self. This is the code: #include <stdio.h> int test53(int y) { int z;int x; for ( x=0; x<10; x=x+1,y=y+1,z=z+1) { if (y<10) { z=z+1; } }return z; } int main() { printf("%d\n", test53(0)); printf("%d\n", test53(5)); printf("%d\n", test53(10)); return 0; } 2.Now I tried using another uninitialized variable a but did not introduce in the loop for an increment it throws warning for -Wall,-Wunintiialized and no warning for -Winit-self,-O2. #include <stdio.h> int test53(int y) { int z;int x;int a; for ( x=0; x<10; x=x+1,y=y+1,z=z+1) { if (y<10) { z=z+1+a; } }return z; } int main() { printf("%d\n", test53(0)); printf("%d\n", test53(5)); printf("%d\n", test53(10)); return 0; } The warning shown is : *<source>:* In function '*test53*': *<source>:8:8:* *warning: *'*a*' may be used uninitialized [ *-Wmaybe-uninitialized*] 8 | *z=z+1+a*; | *~^~~~~~* *<source>:3:19:* *note: *'*a*' was declared here 3 | int z;int x;int *a*; | *^* Compiler returned: 0 3.When I try using it in loop that is giving an increment 'a=a+1' in the for loop, for ( x=0; x<10; x=x+1,y=y+1,z=z+1,a=a+1) the warning thrown by -Wuninitialized is not shown, that is when a variable as soon as it is introduced in the for loop the warning suppresses. There is no warning in the third case. I am not sure but this means when we indulge a uninitialized variable to change its own value by using +,-,*,/ there is no warning but warning arises when directly use it in a task or function. Can you please check this? Hoping for your reply soon. Thanks and Regards, Krishna Narayanan.
