I'm in the process of adding some C++ code to a C codebase. This codebase uses flexible array members in structs. In my understanding GCC supports this as a compiler extension. If I compile my code with lto I get a -Wlto-type-mismatch warning. I added a minimal example to the end of this mail. If I compile the example with > gcc -c -flto a_struct.c > g++ -c -flto b_struct.cc > g++ -Wlto-type-mismatch a_struct.o b_struct.o the last command prints > a_struct.c:3:17: warning: type of ‘my_struct’ does not match original declaration [-Wlto-type-mismatch] > [...] The example is taken from this bug report: https://gcc.gnu.org/bugzilla/show_bug.cgi?id=81440 where GCC erroneously produced this warning for pure C code. Nevertheless, I suspect that in my case the reason for this warning is some error on my side on mixing C and C++. I would be happy if you have any insight into this. (I'm using gcc version 10.3.0) // ab_struct.h typedef struct { int i; int ints[]; } struct_t; // a_struct.c #include "ab_struct.h" extern struct_t my_struct; int main() { return my_struct.ints[0]; } // b_struct.cc #include "ab_struct.h" struct_t my_struct = { 20, { 1, 2 } };