Re: GCC optimization re-order statements

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On 11/06/2021 11:37, Jonny Grant wrote:
> Hello
> This isn't real code, it's just an example to ask this question:
> 
> Would GCC optimizer ever re-order these statements and cause a NULL ptr de-reference SIGSEGV? I recall reading a Chris Lattner paper indicating it could happen.
> 
> void f(int * p)
> {
>     if(!p)
>     {
>         return;
>     }
> 
>     printf("%d\n", *p);
> }
> 
> I which case, a lot of production code faces issues, must be changed to:
> 
> void f(int * p)
> {
>     if(p)
>     {
>         printf("%d\n", *p);
>     }
> }

These two functions have identical semantics.

> 
> Jonny
> 

The optimiser never (baring bugs in the compiler, but those are rare!)
rearranges code in a way that changes side-effects in well-defined code.
 If code hits undefined behaviour, the compiler can do anything.

Thus if you write:

void f2(int *p) {
	int x  = *p;
	if (p) printf("%d\n", x);
}

the compiler can reason that either p is null, or it is not null.  If it
is not null, the "if (p)" conditional is always true and can be skipped.
 If it /is/ null, then dereferencing it to read *p is undefined
behaviour - and the compiler can assume the programmer doesn't care what
happens.

So the code can be optimised to:

void f2(int *p) {
	printf("%d\n", *p);
}


If the compiler knows that on the target in question, it is perfectly
safe (i.e., no signals or anything else) to dereference a null pointer,
then in your original "f" the compiler could read *p before it tests p
for null, but it could not do the printf before the test.  (Sometimes
for embedded systems the compiler knows that reading via a null pointer
is safe.)



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