On Thu, Nov 26, 2020 at 11:46 PM Stefan Ring <stefanrin@xxxxxxxxx> wrote: > > On Thu, Nov 26, 2020 at 11:27 PM Alex Markin <alexanius@xxxxxxxxx> wrote: > > > > memset will not help here. > > True, but only because it is optimized away! :D With -O2, the compiler pre-computes both of them at compile time, and they are both the same (but the upper 6 bytes stay uninitialized, even with memset). With -O0, the compiler pre-computes the first one and calls the library function for the second result, which produces a different result that differs in the last bit. Which is slightly surprising, but nothing that I lose sleep over...
